Shifting nodes in an XML using XSLT

[Hosch]

Hi guys,

I have an XML with following structure

<root>
<header>
<line>
<line>
<line>
<subline>
<subline>
<subline>
<root>


how can I transform the above xml to the following structure using XSLT?
<root>
<line>
<subline>
<line>
<subline>
<line>
<subline>

each line is connected with the appropriate subline using a tag id

Thanks in advance for your support.

[lorela]

Hi,
You can use :

Code: Select all

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

    version="1.0">

    <xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/>

    

    <xsl:template match="/root">

        <xsl:copy>

                <xsl:apply-templates select="line | subline">

                <xsl:sort select="id"/>

            </xsl:apply-templates>

        </xsl:copy>

    </xsl:template>

    

    <xsl:template match="@* | node()">

        <xsl:copy>

            <xsl:apply-templates select="@* | node()"/>

        </xsl:copy>

    </xsl:template>

    

</xsl:stylesheet>

Regards,
Lorela