conditionally rename tags upon data/content

[rabo]

hi,
i cannot figure out how write a XSLT to rename only specific tags and output as XML.

i received xml with "duplicate" xml-tags.
meaning: sometimes the xml-tag <field> should be <field1> and sometime <field2>.
this depends on the xml-tag <field_type> which is put just before <field>.

<field_type>A</fiel_type>
<field>textisenteredhere</field>
<field_type>B</field_type>
<field)textiseneterdherealso, but should have been labeled different</field>


So, if the content of <field_type> = "A" the following <field> should be renamed <field1>. if the content of <field_type> = "B" the following <field> should be renamed <field2>.
The XMl my client has gvenme contains close to 6000 lines, so i would prefer a XSLT to transform this and copy nodes with renamed tags.

thanks for any help

[george]

Hi,

Start with a recursive copy template and then add a match for each case that you want to catch and output field1, field2, etc.

Code: Select all

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

    <xsl:template match="node() | @*">

        <xsl:copy>

            <xsl:apply-templates select="node() | @*"/>

        </xsl:copy>

    </xsl:template>

    <xsl:template match="field[preceding-sibling::*[1][self::field_type and .='A']]">

        <field1>

            <xsl:apply-templates select="node() | @*"/>

        </field1>

    </xsl:template>

    <xsl:template match="field[preceding-sibling::*[1][self::field_type and .='B']]">

        <field2>

            <xsl:apply-templates select="node() | @*"/>

        </field2>

    </xsl:template>

</xsl:stylesheet> 

Best Regards,
George

[rabo]

George,

thanks very much.
it worked perfectly.