XSLT Newbie Help !!

[mfq]

Greetings everyone!

I am trying to render an xml-embedded image through XSLT. (pls if you have an example code for that it would be great help! )

I have the java function which would return a file source on receiving the xml embedded base-64 image string.

The code preview is as follows:

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<xsl:stylesheet version="1.0"

    xmlns:java="http://xml.apache.org/xslt/java"

    xmlns:fn="http://www.mydomain.com/xslt"	

    exclude-result-prefixes="java fn">

. . .

<xsl:variable name="embeddedpic" 

select="formData/instance/EmployeePicture" />

<xsl:variable name="pic" select="fn:com.mydomain.utils.ConversionUtils.base64DecodeString($embeddedpic)"/>

I am getting this exception when calling the above java function from my XSLT

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(XalanXPathException: The function number 'http://xml.apache.org/xslt/java:com.my.utils.ConversionUtils.base64DecodeString' is not available.)

Thanks in advance for info !

Regards

[sorin_ristache]

Hello,

See how you must define a Xalan extension. Use the attribute

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xmlns:fn="xalan://com.mydomain.utils.ConversionUtils"

and call the base64DecodeString method with:

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<xsl:variable name="pic" select="fn:base64DecodeString($embeddedpic)"/>

Regards,
Sorin

[mfq]

Thanks Sorin, I did the change you told and the new error is: Namespace 'xalan:com.mydomain.utils.ConversionUtils' does not contain any functions

[sorin_ristache]

Check that your class com.mydomain.utils.ConversionUtils contains a method base64DecodeString with two parameters of type org.apache.xalan.extensions.ExpressionContext and org.w3c.dom.traversal.NodeIterator and that the class ConversionUtils is set as extension in the transformation scenario.


Regards,
Sorin