how to create link??

[guastoboy]

hello everyone

that's my problem... i know this could be really easy for some of you.. i don't know how to create link using XSL

that's the code in XML

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<back>

<link type="left">pre.xml</link>

<link type="center">home.html</link>

<link type="right">ne.xml</link>

</back>

and this is the output in HTML in wanna have after XSL transformation

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<a href="pre.xml"><img src="aa.jpg"></a>

<a href="home.html"><img src="ab.jpg"></a>

<a href="ne.xml"><img src="ac.jpg"></a>

can someone help me? thank u so much!

[Radu]

Hi,

Here are two ways in which you can do this:

1) Use "xsl:element"

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<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

    <xsl:output indent="yes"/>

    <xsl:template match="back">

        <xsl:for-each select="link">

            <xsl:element name="a">

                <xsl:attribute name="href">

                    <xsl:value-of select="text()"/>

                </xsl:attribute>

                <xsl:element name="img">

                    <xsl:attribute name="src">

                        <xsl:value-of select="@type"/>

                    </xsl:attribute>

                </xsl:element>

            </xsl:element>

        </xsl:for-each>

    </xsl:template>

</xsl:stylesheet>

2)Use XPath expressions directly in attribute values.

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<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

    <xsl:output indent="yes"/>

    <xsl:template match="back">

        <xsl:for-each select="link">

            <a href="{text()}">

                <img src="{@type}"/>

            </a>

        </xsl:for-each>

    </xsl:template>

</xsl:stylesheet>

As you can see the transformer will evaluate what is inside curly brackets in attribute values as XPath expressions.
Here is a good XSLT tutorial: http://www.zvon.org/xxl/XSLTutorial/Boo ... tents.html

Hope this helps,
Regards, Radu.