Trying to display tagname

Post by **lou_boumian** » Sat Nov 10, 2007 11:49 am

I am a translator, not a programmer, and I am completely new to this game.

I have several XML docs of the form:

<content>

  <checklist_c1>

    <ENG>Confirmation</ENG>

    <CHI></CHI>

    <CHT></CHT>

    <RUS></RUS>

    <POL></POL>

    <FIL></FIL>

    <FRE></FRE>

    <VIE></VIE>

    <SPA></SPA>

    <PER></PER>

    <PAN></PAN>

    <HIN></HIN>

  </checklist_c1>

  <checklist_c2>

    <ENG>You need the following three pieces of information as proof you have completed this orientation. Please select one of the options below, then click the</ENG>

    <CHI></CHI>

    <CHT></CHT>

    <RUS></RUS>

    <POL></POL>

    <FIL></FIL>

    <FRE></FRE>

    <VIE></VIE>

    <SPA></SPA>

    <PER></PER>

    <PAN></PAN>

    <HIN></HIN>

  </checklist_c2>

....

</content>

Where I have to introduce the French translation of the English String (value of ENG) into the value of FRE.

I am trying to display these files as tables which will be much easier to handle.

I figured out how to display a table with 2 columns titled:
English and French
with the following XLS file:

Code: Select all


<?xml version="1.0" encoding="iso-8859-1" ?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl"> 

<xsl:template match="node()"> 

<html>

<body>



<table border="2">

<tr>

<th>English</th>

<th>French</th>

</tr>

<xsl:for-each select="content/*">

<tr>	 

<td><xsl:value-of select="ENG" /></td>

<td><xsl:value-of select="FRE" /></td>

</tr>

</xsl:for-each>

</table>

</body>

</html>

</xsl:template>

</xsl:stylesheet>

But I would like to have a first column displaying the tagname of the first child :
checklist_c1, checklist_c2, etc...

I have tried with the following code :

Code: Select all


<?xml version="1.0" encoding="iso-8859-1" ?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl"> 

<xsl:template match="node()"> 

<html>

<body>



<table border="2">

<tr>

<th>Entry #</th>

<th>English</th>

<th>French</th>

</tr>

<xsl:for-each select="content/*">

<tr>	 

<td><xsl:value-of select="name()" /></td>

<td><xsl:value-of select="ENG" /></td>

<td><xsl:value-of select="FRE" /></td>

</tr>

</xsl:for-each>

</table>

</body>

</html>

</xsl:template>

</xsl:stylesheet>

...but it does not work.

(I realize that I don't realy know what I am doing here...)

If anybody has a suggestion, that would help!

Thanks!

Pascal

Post by **jkmyoung** » Tue Nov 13, 2007 5:36 pm

Is content the first node in your xml source? What output are you getting right now?

Post by **jkmyoung** » Tue Nov 13, 2007 5:38 pm

Also you might want to change your xsl namespace to the standard one.
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

It really looks like your xslt should work otherwise.

Post by **lou_boumian** » Wed Nov 14, 2007 8:14 am

Thanks for your suggestion jkmyoung.

When I use my xsl namespace version, I get this error:

The XML page cannot be displayed
Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again later.

--------------------------------------------------------------------------------

Unknown method. -->name()<--

When I use your name space instead of mine, I get this error:

The XML page cannot be displayed
Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again later.

--------------------------------------------------------------------------------

Required attribute 'version' is missing.

Post by **lou_boumian** » Wed Nov 14, 2007 11:17 am

Is content the first node in your xml source?

Yes

Post by **jkmyoung** » Wed Nov 14, 2007 5:37 pm

You probably need version="1.0" in your stylesheet node.

Post by **lou_boumian** » Thu Nov 15, 2007 2:09 am

You probably need version="1.0" in your stylesheet node.

How would you write the namespace then?
I tried <xmlns:xsl="http://www.w3.org/1999/XSL/Transform version="1.0"> and it gives me this error:

The XML page cannot be displayed
Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again later.

--------------------------------------------------------------------------------

A name contained an invalid character. Error processing resource 'file:///D:/checklist_FRE.xml
<xmlns:xsl="http://www.w3.org/1999/XSL/Transform version="1.0">
----------^

Post by **jkmyoung** » Thu Nov 15, 2007 7:36 pm

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

Post by **lou_boumian** » Sat Nov 17, 2007 1:09 am

Post by **lou_boumian** » Sat Nov 17, 2007 2:12 am

So I have this xml file:

Code: Select all

<?xml version="1.0" standalone="yes"?>

<?xml-stylesheet type="text/xsl" href="content.xsl"?>

<content>

  <checklist_c1>

    <ENG>Confirmation</ENG>

    <CHI></CHI>

    <CHT></CHT>

    <RUS></RUS>

    <POL></POL>

    <FIL></FIL>

    <FRE></FRE>

    <VIE></VIE>

    <SPA></SPA>

    <PER></PER>

    <PAN></PAN>

    <HIN></HIN>

  </checklist_c1>

  <checklist_c2>

    <ENG>You need the following three pieces of information as proof you have completed this orientation. Please select one of the options below, then click the</ENG>

    <CHI></CHI>

    <CHT></CHT>

    <RUS></RUS>

    <POL></POL>

    <FIL></FIL>

    <FRE></FRE>

    <VIE></VIE>

    <SPA></SPA>

    <PER></PER>

    <PAN></PAN>

    <HIN></HIN>

  </checklist_c2>

</content>

an this xsl file:

Code: Select all


<?xml version="1.0" encoding="iso-8859-1" ?>

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 

<xsl:template match="node()"> 

<html>

<body>



<table border="2">

<tr>

<th>Entry #</th>

<th>English</th>

<th>French</th>

</tr>

<xsl:for-each select="content/*">

<tr>	 

<td><xsl:value-of select="name()" /></td>

<td><xsl:value-of select="ENG" /></td>

<td><xsl:value-of select="FRE" /></td>

</tr>

</xsl:for-each>

</table>

</body>

</html>

</xsl:template>

</xsl:stylesheet>

and I only get the table shown in previous message:

-------------------------------------
| Entry # | English | French |
-------------------------------------
| Entry # | English | French |
-------------------------------------

instead of the desired result:

Code: Select all


---------------------------------------------------

|    Entry #   |     English         |   French   | 

--------------------------------------------------- 

| checklist_c1 |    Confirmation     |            | 

---------------------------------------------------

| checklist_c2 | You need ...bla bla |            | 

---------------------------------------------------

I tried in IE7 Netscape 8. Same result for both.
Thanks jkmyoung for the tip about the namespace. Anybody else has a suggestion?

Post by **jkmyoung** » Tue Nov 20, 2007 1:25 am

Change your template to:
<xsl:template match="/content">

And your for-each to:
<xsl:for-each select="*">

Post by **lou_boumian** » Tue Nov 20, 2007 8:58 pm

That works. Thanks a lot for your help jkmyoung !
Have a great day!