I want to omit addressLine1 if Address element attribute has

[winkimjr2]

If the type attribute of the Address element = “Standard With Attention” I do not want to display AddressLine1. Instead I want to only display AddressLine2, AddressLine3 and AddressLine4.
My output:
Attn: Michael, 134 W Broadway ST NW, APT 3B, Washington, DC, 12345

Expected output:
134 W Broadway ST NW, APT 3B, Washington, DC, 12345

xml code

Code: Select all

<ProtectedAddresses>

   <Address InternalAddressID="1618613567" Type="Standard With Attention">

      <AddressLine1>Attn: Michael</AddressLine1>

      <AddressLine2>134 W Broadway ST NW</AddressLine2>

      <AddressLine3>APT 3B</AddressLine3>

      <AddressLine4>Washington, DC, 12345</AddressLine4>

   <Attention>James</Attention>

</Address>

</ProtectedAddresses>

xslt code

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<xsl:for-each select="Addresses/Address">

   <xsl:for-each select="ancestor::ProtectionOrder/ProtectionOrderParties/ProtectionOrderParty/DCProtectionOrderPartyAdditional/ProtectedAddresses/Address[@InternalAddressID=current()/@InternalAddressID]">

     <xsl:for-each select="AddressLine1 | AddressLine2 | AddressLine3 | AddressLine4">

       <xsl:value-of select="."/>

       <xsl:if test="position()!=last()">, </xsl:if>

     </xsl:for-each>

     <xsl:text>; </xsl:text>

   </xsl:for-each>

</xsl:for-each>

[lief.erickson]

Since you know that you do not want AddressLine1 included in your output, in your XSLT change

Code: Select all

<xsl:for-each select="AddressLine1 | AddressLine2 | AddressLine3 | AddressLine4">

to

Code: Select all

<xsl:for-each select="AddressLine2 | AddressLine3 | AddressLine4">

-Lief

[winkimjr2]

-Lief thanks for your response!