How do I display timeServed in xsl transformation based on x

[winkimjr2]

How do I use when to display nothing if timeServed="8:25 AM" is not provided in xml document? Right now it is displaying time because there is time in xml. What do I do so when there is no timeServed nothing is displayed?
My xml

Code: Select all

<xsl:template match="NotificationEvent[@notificationType='ProtectionOrderService']">

		<ext:ProtectionOrderService>

			<ext:ProtectionOrderServiceTime>

				<xsl:value-of select="mscef:formatTime(concat(@dateServed,' ',@timeServed))"/>

			</ext:ProtectionOrderServiceTime>

		</ext:ProtectionOrderService>

</xsl:template>

my xsl

Code: Select all

<NotificationEvent notificationType="ProtectionOrderService" timeServed="8:25 AM" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions"></NotificationEvent>

[adrian]

See here example 2:
http://www.w3schools.com/xsl/el_when.asp
So for your case:

Code: Select all

<xsl:when test="@timeServed">

...

Regards,
Adrian

[winkimjr2]

See here example 2:
http://www.w3schools.com/xsl/el_when.asp
So for your case:

Code: Select all

<xsl:when test="@timeServed">

...

Regards,
Adrian

It is now working but I used if instead. Thanks for your help