Schematron and Java

[drakend]

Hello,
I have an xml file structured like this:

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<root>    

    <nodeA>

        <nodeB>

            <nodeC>0</esiste>

            <nodeD>abcd</id_tensione>

            <nodeE>abcd</nodeE>

            <nodeF>0</metri>

        </nodeB>

        <nodeB>

            <nodeC>0</esiste>

            <nodeD>abcd</nodeD>

            <nodeE>abcd</nodeE>

            <nodeF>0</nodeF>

        </nodeB>

    </nodeA>

    <nodeA>

        <nodeB>

            <nodeC>0</nodeC>

            <nodeD>abcd</nodeD>

            <nodeE>abcd</nodeE>

            <nodeF>0</nodeF>

        </nodeB>

        <nodeB>

            <nodeC>0</nodeC>

            <nodeD>abcd</nodeD>

            <nodeE>abcd</nodeE>

            <nodeF>0</nodeF>

        </nodeB>

    </nodeA>

</root>

I validate this xml (I omitted the headers) with this schematron rule called from Java code:

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    <iso:pattern>

        <iso:rule context="nodeB">

            <assert test="exists(nodeF) and nodeF > 0">nodeA[<value-of select="(index-of(../../nodeA, ..)-1)" />].nodeB[<value-of select="(index-of(../nodeB, self::node())-1)" />].nodeF#Some message.  

            </assert>        

        </iso:rule>        

    </iso:pattern>

The sequence index for nodeB is displayed correctly, while the sequence index of nodeA creates problems. It says the operator - cannot operate on a sequence than more than one number, meaning index-of returns more than one index for nodeA. How can this happen? How can avoid it?
Thanks!

[george]

The index-of returns a sequence. Note that what you want is to check for a specific node and in that case you should use generate-id() to obtain a unique number for that node, something like

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index-of(../../nodeA/generate-id(), ../generate-id())-1)

You need a similar change also for nodeB.

Best Regards,
George