XSLTOperation should not expand @class

[xephon]

Hi,

I have a simple ro.sync.ecss.extensions.commons.operations.XSLTOperation for sorting DITA elements. After applying the XSL transformation, the @class attributes are expanded. Because we use DITA, we cannot deactivate the Saxon -expand parameter, because otherwise, elements cannot be selected with the @class selector anymore. So, is it possible (and how) to avoid, that the @class attributes are (permanently) expanded in the XML files?

Greetings,
Stefan

[Radu]

Hi Stefan,

Have you tried instead of probably using xsl:copy-of to apply a copy template in a certain mode so that you can remove the @class attributes from the generated XML content?

Regards,
Radu

[xephon]

Hi Radu,

thanks for your reply. While reading more about modes, I figured out, that I could simply avoid the processing of the attribute by using match="@class".

So I came up with:

Code: Select all

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

    xmlns:xs="http://www.w3.org/2001/XMLSchema"

    xmlns:xd="http://www.oxygenxml.com/ns/doc/xsl"

    exclude-result-prefixes="xs xd"

    version="2.0">

    

  <xsl:output method="xml" indent="no" omit-xml-declaration="yes"/>

  

  <!-- This line has helped -->

  <xsl:template match="@class"/>

  

  <xsl:template match="@* | node()">

    <xsl:copy>

      <xsl:apply-templates select="@* | node()"/>

    </xsl:copy>

  </xsl:template>

  

  <xsl:template match="ul">

    <xsl:copy>

      <xsl:apply-templates select="li">

        <xsl:sort select="(keyword | ph)/@id"/>

      </xsl:apply-templates>

    </xsl:copy>

  </xsl:template>

  

</xsl:stylesheet>

Thanks for your advice, you pointed me to the right direction.


Greetings,
Stefan

[Radu]

Hi Stefan,

Yes, exactly, thanks for posting the solution.

Regards,
Radu