XSL: of a list of xml files, create single DITA files based on the xml element contents
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				oxygen-user
 - Posts: 10
 - Joined: Wed Jan 24, 2024 4:36 pm
 
XSL: of a list of xml files, create single DITA files based on the xml element contents
Post by oxygen-user »
Hi, 
Suppose I have several XML files of the following structure (below).
For each group element, create a DITA file <group-name>.dita that contains all the group elements. (There should be some more configuration/mapping behind it but that's manageable for me.)
If there are same-name groups in an XML file or across XML files, also list those groups.
I tried this in various ways with XSL, etc. but there are always conflicts between same-name groups.
			
			
									
									
						Suppose I have several XML files of the following structure (below).
For each group element, create a DITA file <group-name>.dita that contains all the group elements. (There should be some more configuration/mapping behind it but that's manageable for me.)
If there are same-name groups in an XML file or across XML files, also list those groups.
I tried this in various ways with XSL, etc. but there are always conflicts between same-name groups.
- When I try to merge and split this with one XSL file, then only one same-name group/all same-name groups of one file but not of other files get generated to the output.
 - So I tried merging all XML contents to one file as described in general-xml-questions/topic11375.html. Then I used another xsl stylesheet to generate the output. However, this resulted in a Saxon error: 
(In theory it works better than the first option, so the xsl stylesheet also considers other files with same-name groups. However, if one same-name group is directly followed by another one, then the error occurs.Cannot write more than one result document to the same URI. 
Code: Select all
<?xml version="1.0" encoding="UTF-8" standalone="no"?><configuration>
	
	
	
	<group name="gruppnoans" >
		<parameter name = "testingoans"	value = "true" type="BOOLEAN">
			<description lang="en">English text.. he.</description>
			<description lang="de">... he</description>
		</parameter>
	</group>
	
	
	<group name="gruppnzowa" >
	
		<parameter name="elementoans"		value="false"			type="BOOLEAN">
			<description lang="en">English text a</description>
			<description lang="de">bla bla  a</description>
		</parameter>
		
		<parameter name="element.zwoa"			value="C:\tiger"			type="STRING">
			<description lang="en">English text...</description>
			<description lang="de">bla bla...</description>
		</parameter>
		
		<parameter name="ajkdjfaklsdj"	value="1,MINUTE"		type="PERIOD">
			<description lang="en">English text</description>
			<description lang="de">de</description>
		</parameter>
		
	</group>
	
</configuration>
- 
				xephon
 - Posts: 164
 - Joined: Mon Nov 24, 2014 1:49 pm
 - Location: Greven/Germany
 
Re: XSL: of a list of xml files, create single DITA files based on the xml element contents
This can be done with pure XSLT. But this might take a few hours. You should have a look at the uri-collection() function and the <xsl:result-doxument> instruction. You should be able to develop a solution with these.
			
			
									
									stefan-jung.org – Your DITA/DITA-OT XML consultant
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