XML/XSD Default Element Values
Posted: Wed Jun 20, 2007 7:44 am
Hi,
I'm new to XML, XSD and XSLT.
I was wondering if there is a way to "fill out" an XML document with its default values, as if "expanded" so that my XSLT processor could use these defaults in generating the output.
I think if I had a schema-aware XSLT processor (SAXON-SA), then I could get this done easily as the transformation would be done against an XML document validated against an XSD.
That is not an option for my company for various reasons.
Is there a 2-stage process I can execute (in Java SAX/DOM?) that will "fill out" the required default values for elements or attributes?
I see there are validator classes, but none of these allow me to "write back" the resultant XML(with defaults populated) so that I may use the "expanded" form in subsequent processing.
Thanks,
I'm new to XML, XSD and XSLT.
I was wondering if there is a way to "fill out" an XML document with its default values, as if "expanded" so that my XSLT processor could use these defaults in generating the output.
I think if I had a schema-aware XSLT processor (SAXON-SA), then I could get this done easily as the transformation would be done against an XML document validated against an XSD.
That is not an option for my company for various reasons.
Is there a 2-stage process I can execute (in Java SAX/DOM?) that will "fill out" the required default values for elements or attributes?
I see there are validator classes, but none of these allow me to "write back" the resultant XML(with defaults populated) so that I may use the "expanded" form in subsequent processing.
Thanks,