XSL if-expression question

[jgarrison]

OxygenXML is rejecting the following usage with "Unknown system function: if"
I have XPath level set to 2.0

<xsl:variable name="qd"
select="if(value/qDisplay/text() eq '')
then 'empty'
else 'right'"/>

Is this syntactically correct?

[jgarrison]

My original title is misleading. The if-expression I'm trying to use is defined by XPath, not XSLT.

[george]

Hi,

Where did you set the XPath level to 2.0?
If you edit a stylesheet then you should specify in xsl:stylesheet version="2.0"

Code: Select all

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">

Best Regards,
George

[jkmyoung]

You could always do:
<xsl:variable name="qd">
<xsl:choose>
<xsl:when test="if(value/qDisplay/text() eq '')>empty</xsl:when>
<xsl:otherwise>right</xsl:otherwise>
</xsl:choose>
</xsl:variable>

[Radu]

Hi,

As George said, you have to change the xsl:stylesheet's version attribute to 2.0 in order for it to validate a version 2.0 XPath "if() then else" expression.
This is also true for running a transformation on the stylesheet (you have to run it using the Saxon 8B transformer).
Indeed, if the stylesheet version remains 1.0 you get the error reported above.

Regards,
Radu