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Re: [xsl] XPath function for
On 18/11/2013 14:11, Christian Mahnke wrote:
xmlns:f="data:,f"
well making mode a parameter in general is harder as it's a compile time constant in the normal syntax, but for a fixed mode you can doe
<xsl:copy-of select="a18:field('place', f:apply-templates-filter(node())/>
Note you can't have an implicit default context in user defined functions so you need to pass in the sequence node() explicitly.
David
Re: [xsl] XPath function for ?
Subject: Re: [xsl] XPath function for <xsl:apply-templates/>? From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 18 Nov 2013 14:19:01 +0000 |
On 18/11/2013 14:11, Christian Mahnke wrote:
Hi, might have been asked here before but is there some XPath function that works like <xsl:apply-templates/>? This would be good for readability. Ill give you an example, currently I do this:
<xsl:variable name="content"> <xsl:apply-templates mode="filter"/> </xsl:variable> <xsl:copy-of select="a18:field('place', $content)/>
What Iam asking for would look like this:
<xsl:copy-of select="a18:field('place', apply-templates('filter'))/>
Any thoughts? There is probably an extension for this.
Best, Christian
xmlns:f="data:,f"
well making mode a parameter in general is harder as it's a compile time constant in the normal syntax, but for a fixed mode you can doe
<xsl:function name="f:apply-templates-filter"> <xsl:param name="seq"/> <xsl:apply-templates mode="filter" select="$seq"/> </xsl:function>
<xsl:copy-of select="a18:field('place', f:apply-templates-filter(node())/>
Note you can't have an implicit default context in user defined functions so you need to pass in the sequence node() explicitly.
David
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