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Re: [xsl] JSON-encoding strings in XSLT 2.0
Subject: Re: [xsl] JSON-encoding strings in XSLT 2.0 From: Martynas Jusevičius <martynas@xxxxxxxxxxxx> Date: Tue, 29 Oct 2013 12:02:56 +0100 |
Thanks Michael. I was looking at http://json.org and here's what I came up with: <xsl:template match="text()" mode="json-identity"> <xsl:value-of select="replace(replace(replace(replace(replace(replace(., '\\', '\\\\'), '''', '\\'''), '"', '\\"'), '	', '\\t'), ' ', '\\n'), ' ', '\\r')"/> </xsl:template> Can this be improved? On Tue, Oct 29, 2013 at 10:37 AM, Michael Kay <mike@xxxxxxxxxxxx> wrote: > > There's no built-in function for the job, but picking out the characters = > that need special treatment (e.g. replacing newline by "\n") isn't = > difficult. Handling astral characters is a bit tricky because JSON = > requires them to be represented as a surrogate pair, but again the logic = > for that isn't really difficult. > > Michael Kay > Saxonica > > On 29 Oct 2013, at 00:56, Martynas JuseviD ius <martynas@xxxxxxxxxxxx> wrote: > >> Hey, >> >> is there some way in XSLT 2.0 to encode strings for use in JSON? In my >> case, the stylesheet has to encode all text nodes in a XHTML fragment >> which then gets passed to WYSIWYM editor constructor. Could this be >> done as identity transform? >> >> I had solved this problem when I used XSLT 1.0 on PHP by calling >> json_encode() as extension function, but now I'm in the Java world. >> http://php.net/manual/en/function.json-encode.php >> >> Martynas >> graphityhq.com
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