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Re: [xsl] problem defining param value

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At 2013-01-08 15:32 -0500, Jonina Dames wrote:

used the following syntax in the NEW_STYLESHEET.xsl:

<xsl:variable name="fork1">
<xsl:value-of select="string that returns either 'FORK' or 'SPOON'"/>
</xsl:variable>

<xsl:param name="OUTSIDE_PARAM">
<xsl:if test="$fork1 = 'FORK'">
<xsl:value-of select="string that returns 'VALUE1'"/>
</xsl:if>
<xsl:if test="$fork1 = 'SPOON'">
<xsl:value-of select="string that returns 'VALUE2'"/>
</xsl:if>
</xsl:param>

Unfortunately, the stylesheet is no longer recognizing that a param has been defined at all, and is always defaulting to VALUE3, as determined by the "otherwise" section. It seems to think that $OUTSIDE_PARAM is always empty, even though it's not. Am I missing something completely obvious?

Have you confirmed that $fork1 is being set correctly?

Sounds like an opportunity to throw some diagnostics to the error port:

  <xsl:message>Fork: <xsl:value-of select="$fork1"/></xsl:message>
  <xsl:message>Param: <xsl:value-of select="$OUTSIDE_PARAM"/></xsl:message>

If in your environment you don't have an error port, then you might be able to put diagnostic information into the output using a comment:

  <xsl:comment>Fork: <xsl:value-of select="$fork1"/>
  Param: <xsl:value-of select="$OUTSIDE_PARAM"/></xsl:comment>

(but be careful if this is in the middle of adding attributes to an element as it will choke off the ability to add attributes after adding the comment)

I hope this helps.

. . . . . . . Ken

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