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Re: [xsl] serialized form of XML using xslt 1.0
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Subject: Re: [xsl] serialized form of XML using xslt 1.0 From: Andrew Welch <andrew.j.welch@xxxxxxxxx> Date: Fri, 7 Dec 2012 13:32:00 +0000 |
Great, thanks. On 7 December 2012 12:50, Michael Kay <mike@xxxxxxxxxxxx> wrote: > > You output xmlns="" if the following condition is true: > > $this/../namespace::*[name()=''] and not($this/namespace::*[name()='']) > > Michael Kay > Saxonica > > > On 07/12/2012 12:24, Andrew Welch wrote: >> >> Given: >> >> <foo xmlns="aaa"> >> <bar xmlns=""> >> <bbb/> >> </bar> >> <baz/> >> </foo> >> >> What is the XSLT 1.0 way to create that exactly output as a string - >> I'm struggling to think how to handle the namespaces with out the >> functions from xpath 2.0. >> >> For example, how do you avoid outputting xmlns="" for <bbb/> ? >> >> thanks in advance, > -- Andrew Welch http://andrewjwelch.com
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