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Re: [xsl] Re: position last and attributes

Subject: Re: [xsl] Re: position last and attributes
From: Ihe Onwuka <ihe.onwuka@xxxxxxxxxxxxxx>
Date: Wed, 26 Sep 2012 12:31:19 +0100

that is definitely a plan. a better solution and an answer to my other
query from andrew..... great.

On Wed, Sep 26, 2012 at 12:26 PM, Wolfgang Laun <wolfgang.laun@xxxxxxxxx> wrote:
> string-join() ?
> -W
> On 26/09/2012, Ihe Onwuka <ihe.onwuka@xxxxxxxxxxxxxx> wrote:
>> On Thu, Sep 20, 2012 at 7:13 AM, Ihe Onwuka <ihe.onwuka@xxxxxxxxxxxxxx>
>> wrote:
>>> It would seem (somewhat paradoxically) that given the definition of
>>> position() and last() they could be applied to @* which is
>>> intrinsically unordered.
>> So seeking to output all the attributes of an element comma separated
>> (by all means correct me if I miss the obvious).
>> If I have done apply-templates select="@*" and have
>> <xsl:template match="@*">
>>      < code to output the attribute>
>>      <!-- do I put a comma or not -->
>>      <xsl:if test=". is ../@*[last()]>,</xsl:if>
>> the specification doesn't guarantee that ../@* is in the same order of
>> the node-set returned by @* when the apply-templates was done.
>> So either I have to put the @* in a variable and do my if test on that
>> to ensure I am dealing with the same node-set  or I match on the
>> parent element instead of @* and for-each through  @* and decide where
>> to put my commas that way.
>> Or have I got that wrong.

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