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Re: [xsl] position() function in loop provides only 1

Subject: Re: [xsl] position() function in loop provides only 1
From: henry human <henry_human@xxxxxxxx>
Date: Wed, 11 Apr 2012 14:08:35 +0100 (BST)

I now that the position() reset after a loop is ended and I am not expecting
some thing else .
In my case the position () provides correctly the POSITION
for each loop in the FIRST loop but 
in the other loop (xsl:for-each
select="taxtotal)B the position() function provides everB ONE and does not
Regarding number function I do not now how to use it here. and I
think you are wrong, in XSLT you canbt save value to a variable and use it
Kind regards

----- UrsprC<ngliche Message -----
Von: Michel
Hendriksen <michel.hendriksen@xxxxx>
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Gesendet: 14:06 Mittwoch, 11.April 2012
Betreff: Re: [xsl] position() function
in loop provides only 1

In for each the context will switch, so position will
be reset inside
You could keep position in a variable if you need it.

On Wed, Apr 11, 2012 at 1:57 PM, henry human <henry_human@xxxxxxxx> wrote:
Hi all
> I use the positon() funciton to build a counter.
> I use it in a
for-each loop under another for-each. The result is but ever 1.
> Strange, but
inB the same document in the first for-each loop it works fine (bellow is
first loop,B for-each select="Item)
> sample document look like this:
<xsl:for-each select="Item">
> <it>
> <xsl:value-of select=" position()">
> <xsl:value-of select=" position()">
> </it>
> ........
> <it>
//positionB  = 113
> </it>
> </xsll:for-each>
> <xsl:for-each
> B B  <xsl:for-each select="taxtotal">
> ....
<xsl:value-of select=" position()">
> B B  </xsll:for-each>
B B </xsll:for-each>
> ------
> <invoiceLine>
> <taxtoatl>
> </taxtoal>
> </taxtotal>
> ...........
> </invoiceLine>
> kind regards
> Henry
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