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RE: [xsl] how to achieve this ?

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Thanks,



It solved the id problem but the menu still don't work right.

It still don't work as as accordian menu. See http://test.tamarawobben.nl



Roelof









---------------------------------------- > From: bbosgoed@xxxxxxx > Date: Mon,
23 Jan 2012 08:35:36 +0100 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject:
Re: [xsl] how to achieve this ? > > > Op 23 jan 2012, om 08:26 heeft Roelof
Wobben het volgende geschreven: > > Not knowing how the input looks like, i
would say that: > <ul class="menu" id={concat('menu', @value)}> > > should do
it for you, its a short notation for xsl:value-of select > > > > For a menu I
have to take care that every <menu class> get a unique id. > > > > I thought
this would work : > > > > <xsl:template match="year"> > > <ul class="menu" id=
"concat ('menu', @value)" > > > <li> > > <a href="#"> <xsl:value-of
select="@value"/> </a> > > <ul class="acitem"> > > <xsl:apply-templates
select="month" /> > > </ul> > > </li> > > </ul> > > </xsl:template> > > > >
But it don't work. > > > > Do I have to use here <xsl:value-of> or is there a
better way ? > > >

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