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RE: [xsl] merging sequences

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Hi Ken, Andrew and David.
First of all, thank you very much for these smart answers.
I think I will learn much from them.
Regarding my specific needs, Ken's solution fits better since the order is
exactly as expected
N112,N100,N107,P2010,N109,P2014,P2015,N108,N203,N306,N206,N307,N311
When David's output is
N112 N100 N107 N306 P2010 N109 P2014 P2015 N108 N203 N206 N307 N311

I will now put it in a real life conditions and see if with other inputs it
still performs well.
Thanks again to you all since it was really (at least for me) a tough problem
:)

Kind regards,
Fabien





-----Message d'origine-----
De : G. Ken Holman [mailto:gkholman@xxxxxxxxxxxxxxxxxxxx]
Envoyi : vendredi 13 janvier 2012 17:28
@ : xsl-list@xxxxxxxxxxxxxxxxxxxxxx; xsl-list@xxxxxxxxxxxxxxxxxxxxxx;
xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Objet : Re: [xsl] merging sequences

At 2012-01-13 10:48 -0500, I wrote:
>At 2012-01-13 14:41 +0000, Fabien Tillier wrote:
>>I have the two following sequences
>>N112 N100 N107 P2010 N109 P2014 P2015 N108 N203 N206 N307 N311
>>And
>>N112 N100 P2014 P2015 N108 N203 N306 N206 N307 N311
>>...
>>I would like to align these so that the resulting sequence contains
>>all items, but keeping the order, thus
>>...
>>N112 N100 N107 P2010 N109 P2014 P2015 N108 N203 N306 N206 N307 N311
>
>I hope the example below helps.  It bases a sort on expressing each
>item's location in its own sequence and the other sequence.

I didn't give you the result as a variable, only as output.  The
example below gives you a variable of strings you can then work with.

I hope this helps.

. . . . . . Ken

T:\ftemp>xslt2 fabien.xsl fabien.xsl
N112,N100,N107,P2010,N109,P2014,P2015,N108,N203,N206,N307,N311
N112,N100,P2014,P2015,N108,N203,N306,N206,N307,N311
N112,N100,N107,P2010,N109,P2014,P2015,N108,N203,N306,N206,N307,N311

T:\ftemp>type fabien.xsl
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
   xmlns:xsd="http://www.w3.org/2001/XMLSchema"
   version="2.0">
   <xsl:output method="text"/>

   <xsl:template match="/">
   <!--input sequences-->
   <xsl:variable name="seq1" select="tokenize('N112 N100 N107 P2010
N109 P2014 P2
015 N108 N203 N206 N307 N311','\s+')"/>
   <xsl:variable name="seq2" select="tokenize('N112 N100 P2014 P2015
N108 N203 N3
06 N206 N307 N311','\s+')"/>

   <!--order them with information about their position in other sequence-->
   <xsl:variable name="items1">
     <xsl:for-each select="$seq1">
       <item index="{position()}" other="{index-of($seq2,.)[1]}">
         <xsl:value-of select="."/>
       </item>
     </xsl:for-each>
   </xsl:variable>
   <xsl:variable name="items2">
     <xsl:for-each select="$seq2">
       <item index="{position()}" other="{index-of($seq1,.)[1]}">
         <xsl:value-of select="."/>
       </item>
     </xsl:for-each>
   </xsl:variable>

   <xsl:variable name="seq" as="xsd:string*">
     <!--order the result based on relative positions-->
     <xsl:for-each select="$items1/item,$items2/item[@other='']">
       <xsl:sort select="(:the relative order is latest of self or other:)
                  max((number(@index),
                       if(@other='') (:if no other, then use previous other:)
                         then
preceding-sibling::*[@other!=''][1]/number(@other)
                         else number(@other)))"/>
       <xsl:sequence select="."/>
     </xsl:for-each>
   </xsl:variable>

   <!--reveal inputs and outputs-->
   <xsl:value-of select="$seq1" separator=","/><xsl:text>&#xa;</xsl:text>
   <xsl:value-of select="$seq2" separator=","/><xsl:text>&#xa;</xsl:text>
   <xsl:value-of select="$seq" separator=","/><xsl:text>&#xa;</xsl:text>
</xsl:template>

</xsl:stylesheet>
T:\ftemp>

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