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On 06/01/2012 08:54, henry human wrote:
Please start a new thread for new questions, don't reply to a previous one (even if you change the subject) This is in the
"[xsl] including an XSLT 1.0 stylesheet in a XSLT 2.0 one"
thread.
It's not clear exactly what output you want, but perhaps
<xsl:number level="any"/>
is your friend.
David
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Re: [xsl] build a counter variable
Subject: Re: [xsl] build a counter variable From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 06 Jan 2012 09:17:03 +0000 |
On 06/01/2012 08:54, henry human wrote:
Please start a new thread for new questions, don't reply to a previous one (even if you change the subject) This is in the
"[xsl] including an XSLT 1.0 stylesheet in a XSLT 2.0 one"
thread.
Hi
I have an XSLT structure as bellow. I tried to build a counter with the position () function .But it does not work because the position () function ever begins with 1 in a loop. (In node1, node2, node3 the position begins with 1 (position= 1))
<xsl:for-each select="node1/m"> <m><xsl:value-of select="position()"/> </m> <== position should be 1 ....... <xsl:for-each select="node1/node2/a"> <a>....</a> <== position = 2 <a>....</a> <== position = 3 <a>.....</a> <== position = 4 </xsl:for-each>
<xsl:for-each select="node1/node3/f1">
<f1><xsl:value-of select="position()"/></f1> <== position = 5 </xsl:for-each>
</xsl:for-each>
It's not clear exactly what output you want, but perhaps
<xsl:number level="any"/>
is your friend.
Thanks for any help
David
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