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[xsl] Obtaining the base output uri from within xsl

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Hi,

I've been looking at the xsl functions for some way of gaining the base output
uri, or better still, the output document name. I can find how to get the
input document, the static context, but not the output document name.

I'm using Saxon with the -o parameter, so I could add an extra parameter to my
stylesheet such as "outputURI=x", but that would seem messy.

I'm sure it's really obvious, but I've not found anything yet.

Thanks in advance.

Clint.

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