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Re: [xsl] layout problem

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On 08/12/2011 10:34, Roelof Wobben wrote:

all your code is in a template with name section-content but you never call a template of that name (named templates are invoked using xsl:call-template) so your stylesheet is equivalent to a stylesheet with no temnplates, so will just produce character data and no elements.

it looks like you want to be using template matching and apply-templates
rather than named-templates and xsl:for-each.

David

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