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(1) An attribute name variable:
Is it possible to write
<xsl:for-each select="../Stamp/Formats/@souvenir-sheet">
in such a way that @souvenir-sheet is replaced by a variable representing other attributes so that the same statement could be used to service a different specific <Formats> attribute? i.e, xsl:for-each select="../Stamp/Formats/@minisheet"> "Any" will not work, the name has to be specific.
(2) Selecting from the attribute axis:
in the <Stamp> element below , is it possible to select the element <CatNumber>'s attribute: pofis-number?
i.e.,
<xsl:variable name="file-name" select="concat([some XPath expression?]CatNumbers/@pofis-number, '.htm')"/>
I really hope the answers are yes and that you can tell me how. I tried to find this info in Michael's book, but failed.
Thanks,
Mark
[xsl] XPath questions: selecting from an attribute node axis and an attribute name variable
Subject: [xsl] XPath questions: selecting from an attribute node axis and an attribute name variable From: "Mark" <mark@xxxxxxxxxxxx> Date: Fri, 30 Sep 2011 16:47:49 -0700 |
Hi, I am using XSLT 2.0. and have two questions I have been unable to resolve:
(1) An attribute name variable:
Is it possible to write
<xsl:for-each select="../Stamp/Formats/@souvenir-sheet">
in such a way that @souvenir-sheet is replaced by a variable representing other attributes so that the same statement could be used to service a different specific <Formats> attribute? i.e, xsl:for-each select="../Stamp/Formats/@minisheet"> "Any" will not work, the name has to be specific.
(2) Selecting from the attribute axis:
From within the context provided by the execution ofxsl:for-each select="../Stamp/Formats/@souvenir-sheet">
in the <Stamp> element below , is it possible to select the element <CatNumber>'s attribute: pofis-number?
i.e.,
<xsl:variable name="file-name" select="concat([some XPath expression?]CatNumbers/@pofis-number, '.htm')"/>
XML fragment <Stamp> <CatNumbers scott-number="3040" scott-suffix="a" pofis-number="174"/> <Formats souvenir-sheet="174"/> </Stamp>
I really hope the answers are yes and that you can tell me how. I tried to find this info in Michael's book, but failed.
Thanks,
Mark
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