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Re: [xsl] Count items in a key ?


Subject: Re: [xsl] Count items in a key ?
From: Dimitre Novatchev <dnovatchev@xxxxxxxxx>
Date: Wed, 13 Oct 2010 11:50:59 -0700

On Wed, Oct 13, 2010 at 11:25 AM, Olivier Jeulin
<olivier.jeulin@xxxxxxxxx> wrote:
> Le 13/10/2010 19:50, Dimitre Novatchev a C)crit :
>>
>> On Wed, Oct 13, 2010 at 8:23 AM, Scott Trenda<Scott.Trenda@xxxxxxxx>
>> B wrote:
>>>
>>> New XSLT 2.1 feature? :)
>>
>>
>> Could be something as:
>>
>> B  B  B  keys(keyname as xs:string) as item()*
>>
>> and an additional overload:
>>
>> B  B  B  keys(keyname as xs:string, document as document-node()) as
item()*
>
> Yes, it looks fine. But keys are atomized, so shouldn't keys() return
> xs:anyType* instead of item()* ?


Did you mean xs:anyAtomicType*   ? Yes, this is precise.


--
Cheers,
Dimitre Novatchev
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Truly great madness cannot be achieved without significant intelligence.
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To invent, you need a good imagination and a pile of junk
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