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On 28/07/2010 17:11, Wolfgang Laun wrote:
would return the elements you want.
However the predicates that appear within a step are not filtering the entire sequence returned they are a separate syntactic construct, and they number in the direction of the axis used. which is backwards for ancestor-or-self so, as you observe
ancestor-or-self::*[position() != last()]
selects the same elements.
David
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Re: [xsl] ancestor::* and for-each
Subject: Re: [xsl] ancestor::* and for-each From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 28 Jul 2010 17:27:19 +0100 |
On 28/07/2010 17:11, Wolfgang Laun wrote:
I use ancestor-or-self::* to obtain the node sequence from some node to the document root. The outermost/top element of the document isn't interesting, so I add a predicate, and I find that this works: [position() != last()] Apparently, the sequence goes from leaf to root, which is the closing tag order, as it should be.
The sequence returned by a path expression is always in document order so (ancestor-or-self::*)[position()!=1]
would return the elements you want.
However the predicates that appear within a step are not filtering the entire sequence returned they are a separate syntactic construct, and they number in the direction of the axis used. which is backwards for ancestor-or-self so, as you observe
ancestor-or-self::*[position() != last()]
selects the same elements.
[] in a step is a predicate http://www.w3.org/TR/xpath20/#id-predicates
[] applied to a sequence is a filter http://www.w3.org/TR/xpath20/#id-filter-expr
David
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