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Re: [xsl] Transforming xml with any namespace
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Subject: Re: [xsl] Transforming xml with any namespace From: Florent Georges <lists@xxxxxxxxxxxx> Date: Wed, 25 Nov 2009 14:25:11 +0000 (GMT) |
Anders Viklund wrote:
> <xsl:template match="//*[local-name()='Type1']">
You can use the XPath 2.0 namespace wildcard:
<xsl:template
match="*:Type1">
--
Florent Georges
http://www.fgeorges..org/
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