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At 2009-06-18 23:24 +0100, Badrul Anuar wrote:
Above you are always selecting the first one, so you are always getting the first one in your result.
If you want the attribute with the entry matched, use:
<xsl:value-of select="@name"/>
... and:
<xsl:value-of select="@CVSS_base_score"/>
By working with a relative address, rather than addressing the first entry every time you match any entry.
I hope this helps.
. . . . . . . . Ken
Re: [xsl] XSL with namespace from NVD
Subject: Re: [xsl] XSL with namespace from NVD From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Thu, 18 Jun 2009 16:22:57 -0400 |
At 2009-06-18 23:24 +0100, Badrul Anuar wrote:
And I use the XSL with this code
----XSL-start------------ <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:b="http://nvd.nist.gov/feeds/cve/1.2" version="1.0"> <xsl:output method="html"/>
<xsl:template match="//b:entry">
<div> <xsl:number format="1."/> <xsl:value-of select="//b:entry/@name"/>
Above you are always selecting the first one, so you are always getting the first one in your result.
If you want the attribute with the entry matched, use:
<xsl:value-of select="@name"/>
<xsl:text> : </xsl:text>
<xsl:value-of select="//b:entry/@CVSS_base_score"/>
... and:
<xsl:value-of select="@CVSS_base_score"/>
My question is how to make sure the output is taken for each entry.
By working with a relative address, rather than addressing the first entry every time you match any entry.
I hope this helps.
. . . . . . . . Ken
-- Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Training tools: Comprehensive interactive XSLT/XPath 1.0/2.0 video Video lesson: http://www.youtube.com/watch?v=PrNjJCh7Ppg&fmt=18 Video overview: http://www.youtube.com/watch?v=VTiodiij6gE&fmt=18 G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Male Cancer Awareness Nov'07 http://www.CraneSoftwrights.com/s/bc Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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