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RE: [xsl] Error when params are in Xpath expression

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Variable references such as $toLang can be used in place of literal values.
They can't be used in place of arbitrary fragments of XPath expression text
(they aren't macros). If $toLang is an element name, then you can find
elements of that name using *[name()=$toLang].

Regards,

Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay 

 

> -----Original Message-----
> From: Dmitri Snytkine [mailto:d.snytkine@xxxxxxxxx] 
> Sent: 12 May 2009 12:06
> To: xsl-list
> Subject: [xsl] Error when params are in Xpath expression
> 
> <!-- get translation of a string -->
>     <xsl:template name="translateString">
>         <xsl:param name="str" select="'recent_albums'"/>
>         <xsl:param name="toLang"/>
>         <xsl:param name="fallback" select="'en'"/>
> 		
>         <xsl:choose>
>             <xsl:when test="true()">
> 
> 				<xsl:value-of
> select="document('')/*/trans:tr/tr_string[@str=$str]/$toLang"/>
>             </xsl:when>
>             <xsl:otherwise>
>                 <xsl:value-of select="'not found'"/>
>             </xsl:otherwise>
>         </xsl:choose>
>     </xsl:template>
> 
> 
> I get errors when running this template.
> If I manually replace the $str and $toLang, then I am getting 
> the correct result.
> 
> <xsl:value-of 
> select="document('')/*/trans:tr/tr_string[@str='recent_images']/ru"/>
> 
> What is wrong with my syntax that uses params? Are params 
> allowed in Xpath expression?

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