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Re: [xsl] Get value from $Variable


Subject: Re: [xsl] Get value from $Variable
From: Michael Nielsen <xsl-list@xxxxxxxxxx>
Date: Tue, 17 Mar 2009 11:29:20 +0100

Hi Florent and Michael

Thank you about the current() - I'll go for that since I dont like
declaring the variable on every walk.

@Florent, sorry about my name :) -- I have changed it in my Thunderbird ;)

Med venlig hilsen
Michael Nielsen

Se min fotoblog pe:

www.photofolio.dk - A study in photography
<http://feeds.feedburner.com/%7Er/photofoliodk/%7E6/1>




Michael Kay wrote:
>> This code was crappy and has been changed to this:
>>
>>      <xsl:for-each select="Weekdays/Day">
>>           <xsl:variable name="Current_Id" select="@Id"/>
>>           <xsl:value-of 
>> select="$Language/Weekdays/Weekday[@Wd_Id = 
>> $Current_Id]"/><xsl:if test="following-sibling::*[1]">, </xsl:if>
>>      </xsl:for-each>
>>
>> But I would like to skip the Current_Id variable, but when I 
>> do like this:
>>
>>      <xsl:for-each select="Weekdays/Day">
>>           <xsl:value-of 
>> select="$Language/Weekdays/Weekday[@Wd_Id = @Id]"/><xsl:if 
>> test="following-sibling::*[1]">, </xsl:if>
>>      </xsl:for-each>
>>
>>     
>
> You can write select="$Language/Weekdays/Weekday[@Wd_Id = current()/@Id]"
>
> Personally, though, I think I prefer the variable.
>
> Michael Kay
> http://www.saxonica.com/


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