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Mike Stroud wrote:
Here is an XSLT 1.0 stylesheet:
<xsl:output method="xml" indent="yes"/>
<xsl:template match="cd">
<xsl:copy>
<xsl:copy-of select="title"/>
<artist>
<xsl:value-of select="../../artists/artist[number = current()/number]/name"/>
</artist>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
--
Re: [xsl] Re-arranging an XML file
Subject: Re: [xsl] Re-arranging an XML file From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Tue, 13 Jan 2009 14:45:21 +0100 |
Mike Stroud wrote:
Is there an easy way for an XSL rookie to transform it to look more like this?
Here is an XSLT 1.0 stylesheet:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="Catalog"> <xsl:copy> <xsl:apply-templates select="cds/cd"/> </xsl:copy> </xsl:template>
<xsl:template match="cd">
<xsl:copy>
<xsl:copy-of select="title"/>
<artist>
<xsl:value-of select="../../artists/artist[number = current()/number]/name"/>
</artist>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
--
Martin Honnen http://JavaScript.FAQTs.com/
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