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[xsl] Without parentnode, how to matchng first and last position of the list-item
Subject: [xsl] Without parentnode, how to matchng first and last position of the list-item From: "V.Ramkumar" <v.ramkumar@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 12 Nov 2008 17:00:17 +0530 |
Hi List, Input, <p class="FeatureListNumbered">1.Stand in a line in front.</p> <p class="FeatureListNumbered">2.Which month has the most birthdays?</p> <p class="FeatureH1">Problem Guide:</p> <p class="FeatureListNumbered">1.Stand in a line in front.</p> <p class="FeatureListNumbered">2.Which month has the most birthdays?</p> Output, <list1 type="1"> <item1><p>Stand in a line in front.</p></item1> <item1><p>Which month has the most birthdays?</p></item1> </list1> <sect1><title>Problem Guide:</title> <list1 type="1"> <item1><p>Stand in a line in front.</p></item1> <item1><p>Which month has the most birthdays?</p></item1> </list1> XSL, <xsl:template match="p[starts-with(@class, 'FeatureListNumbered')]"> <item1><p><xsl:apply-templates/></p></item1> </xsl:template> Please suggest how to handle this issue. Note: In the above input no parent tag for the list. Regards, Ramkumar.
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