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[xsl] calculating relative position in document order

Subject: [xsl] calculating relative position in document order
From: tom s <tshmit@xxxxxxxxx>
Date: Thu, 16 Oct 2008 09:53:33 -0700 (PDT)


I'd like to be able to determine which element is "closer", in terms of document order, to a given element. eg, given two structures containing siblings:


I'd like to detect that the second structure is "out of order". In my fantasy pseudo code, I might express the constraint as:

//c[positionEX(preceding::a[1]) > positionEX(preceding::b[1])]

Where my fantasy positionEX() function returns the absolute position of the argument in the document. 

Am I missing something, or is implementing this operation in real xpath/xslt much more difficult than it seems it should be?

Thanks in advance for any help...


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