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RE: [xsl] Date YYYYMMDD format XSLT 2.0 (with string Update)

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<chapter version="Feb. 2000"/>
<chapter version="Oct. 2006 Update">


Apart from this I need to ignore attributes values with "Update" (<chapter
version="Dec. 2003 Update">) which I will be able to handle with string
check (contains() function)



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Once again, is the below code is correct for "xsl:analyze-string" for cases
where @version contains string ' Update'. 

<xsl:analyze-string select="substring-before(string(./@version), ' Update')"
regex="{ $re }">

 seems to error in select="" though XMLSpy does not gives any error. I am
trying to conditional test of @version with and without 'Update' string.

Thanks

 

> -----Original Message-----
> From: Pankaj Chaturvedi [mailto:pankaj.chaturvedi@xxxxxxxxx]
> Sent: 16 September 2008 09:49
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Date YYYYMMDD format XSLT 2.0
> 
> 
> Hi,
> 
> I have an element which has the date in the below format in an
> attribute:
> 
> Input
> ================
> <chapter version="Feb. 2000"/>
> 
> The date could be optional can be taken as 01 by default. So the 
> desired output required in "YYYYMMDD format".
> 
> Output Required
> ================
> <chapter version="20000201"/>
> 
> 
> I've been going thru the Michael Kay's book and found it has an 
> example which does the trick vice versa. I mean YYYYMMDD to 01 Feb 
> 2000 for instance.
> 
> I am using the  XSLT 2.0 and thinking of using translate() functions 
> (for
> months) to get this done. Is there any better way to achieve this? Any 
> suggestions will be highly appreciated.
> 
> Best,
> 
> Pankaj Chaturvedi
> 
> ==============================================================
> ==============
> ================
> 
> 
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