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[xsl] Searching for specific character in string and outputting first 4 digits that follow
Subject: [xsl] Searching for specific character in string and outputting first 4 digits that follow From: Sharon_Harris@xxxxxxxxxxxxxxxxxxxx Date: Tue, 9 Sep 2008 08:12:26 -0400 |
I am trying to figure out how to search for the 2nd instance of a character in a string and then output only the first 4 digits that follow this character. For the PubDate element, I want to find the 2nd instance of the back slash ("/") and then output the 4-digit year that follows this back slash. In the following example, I want to output "2008'. <PubDate>5/12/2008 3:13:14 PM</PubDate> I want to output the year so it displays in paragraph hardcoded into the stylesheet. For example, <p>)<PubDate Year><xsl:text> TheAxsl-list@xxxxxxxxxxxxxxxxxxxxxxxx Group, Inc.</xsl:text></p> I know something like this can be achieved using <xsl:value-of select="PubDate"> but don't know the logic/argument to pass to search the back slash and output the year that follows it. Thanks for your help! _______________________________ Sharon Goldner Harris Knowledge Management Evangelist Ultimate Software Group 704-660-6482 Confidentiality Note: This e-mail message and any attachments to it are intended only for the named recipients and may contain legally privileged and/or confidential information. If you are not one of the intended recipients, do not duplicate or forward this e-mail message.
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[xsl] Validate xml against dtd in p, Kjellaug Johansen | Thread | RE: [xsl] Searching for specific ch, Michael Kay |
[xsl] Validate xml against dtd in p, Kjellaug Johansen | Date | RE: [xsl] Searching for specific ch, Michael Kay |
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