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sudheshna iyer wrote:
I think you should be able to do
<xsl:apply-templates
select="/Announcements/announcement | document('File3.xml')/Annoucements/announcement">
<xsl:sort select="translate(anc_date, '-', '')"
data-type="number"
order="descending"/>
</xsl:apply-templates>
--
Re: [xsl] Combine two diff xmls - Sorting by date
Subject: Re: [xsl] Combine two diff xmls - Sorting by date From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Thu, 29 May 2008 13:26:35 +0200 |
sudheshna iyer wrote:
From xsl of File2.xml:<xsl:apply-templates select="* | document('File3.xml')/*"/> ==> IS THIS CORRECT? Step3: Now File2Xsl contains File2.xml and File3.xml
Step4: But when I process combined XML, each XML is getting processed as two files. I am not seeing one x
I think you should be able to do
<xsl:apply-templates
select="/Announcements/announcement | document('File3.xml')/Annoucements/announcement">
<xsl:sort select="translate(anc_date, '-', '')"
data-type="number"
order="descending"/>
</xsl:apply-templates>
--
Martin Honnen http://JavaScript.FAQTs.com/
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