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[xsl] how to get detailed information of XSL by javascript
Subject: [xsl] how to get detailed information of XSL by javascript From: shiwudao <shiwudao@xxxxxxxxxxx> Date: Wed, 30 Jan 2008 03:04:13 +0000 |
Hi, Anybody knows how to get detailed error message when I use Javascript/XSLTProcessor() under Firefox. For example, I wrote a XSL1.0 XSL file like: ... < xsl:if test=" $ level & g t 2 "> ... There should be " & gt; ", but I wrote " & g t " When I call var xsltProcessor = new XSLTProcessor(); xsltProcessor.importStylesheet(myxsl); There will throw an exception with the error message: XSLT-Component returned failure code: 0x80600001 [nsIXSLTProcessor.importStylesheet] I do not think this information can give more about the error reason. But in the error console of FireFox, it will display an error message like: error: source:http s:// xxx.xxx.xxx.com:xxx/xxx/xsl/test.xsl line:45 column:27 source: --------------------------^ The question is how can get this error message by javascript? thank you. _________________________________________________________________ LlA9AK#,LmRBAK#,PD6/AK#,!0F_<~!1AK http://get.live.cn
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