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Sean Tiley wrote:
Well if you want to copy everything (the XSLT data model covers) then
<xsl:template match="/">
<xsl:copy-of select="/"/>
</xsl:template>
suffices but that is not an approach where you can work in additional templates. With the identity transformation template written as
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
you can add templates to override the template for nodes that you want to change. So using xsl:copy for a shallow copy and xsl:apply-templates to process attributes and child elements gives additional templates a chance to be applied on each step.
--
Re: [xsl] xpath query
Subject: Re: [xsl] xpath query From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Sat, 19 Jan 2008 18:57:02 +0100 |
Sean Tiley wrote:
2) - Also related to the first template. Why do I need the <xsl:template match="@* | node()"> and <xsl:apply-templates select="@* | node()"/> in the <xsl:copy/> tag? I would have thought in the template match "/" would have sufficed. (When I try that, I just get the values from the nodes).
Well if you want to copy everything (the XSLT data model covers) then
<xsl:template match="/">
<xsl:copy-of select="/"/>
</xsl:template>
suffices but that is not an approach where you can work in additional templates. With the identity transformation template written as
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
you can add templates to override the template for nodes that you want to change. So using xsl:copy for a shallow copy and xsl:apply-templates to process attributes and child elements gives additional templates a chance to be applied on each step.
--
Martin Honnen http://JavaScript.FAQTs.com/
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