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Re: [xsl] position() outside for-each

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Yu don't say waht is wrong with the code that you posted 9if the
template for root did xsl:appy-templates select="item"/> you'd probably
get the number you wanted. position() works the same way in
aapply-templates as it does in for-each, in both cases the number is
essentially unrelated to the position of teh node in the input, although
in particular cases it will be the same. <xsl:number/> is a safer way of
generating mumbers in the utput.


David

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