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Subject: [xsl] Fwd: level grouping problem From: "Maria Shvedova" <shvedova.maria@xxxxxxxxx> Date: Thu, 6 Sep 2007 12:24:25 +1000 |
Hi all,
My appologies in advance for the possible incorrect use of
terminology, I'm still new to xslt.
I have an xml file that looks like that:
<export>
<references>
<reference>
<detail name="Detail1">
<title>Detail 1 text</title>
</detail>
<detail name="Detail2">
<title>Detail2 text</title>
</detail>
<detail name="Detail2">
<title>Detail2 text</title>
</detail>
</reference>
<reference>
<detail name="Detail1">
<title>Detail 1 text</title>
</detail>
<detail name="Detail2">
<title>Detail2 text</title>
</detail>
<detail name="Detail2">
<title>Detail2 text</title>
</detail>
</reference>
</references>
</export>
and the output that I'm trying to achieve is the following: (the
grouping needs to occur within each <reference> tag, i.e. I need to
get)
Detail1
Detail 1 text
Detail2
Detail2 text
Detail2 text
Detail1
Detail 1 text
Detail2
Detail2 text
Detail2 text
what is happening instead, though, is that elements are being grouped
together, so the output that I get is:
Detail1
Detail 1 text
Detail 1 text
Detail2
Detail2 text
Detail2 text
Detail2 text
Detail2 text
here is the stylesheet that I'm using:
<xsl:stylesheet xmlns:xsl=" http://www.w3.org/1999/XSL/Transform "
version="1.0">
<xsl:key name="det" match="/export/references/reference/detail" use="@name"/>
<xsl:template match="/export/references">
<html>
<body>
<table>
<xsl:apply-templates select="reference"/>
</table>
</body>
</html>
</xsl:template>
<xsl:template match="reference">
<xsl:for-each
select="detail[generate-id(.)=generate-id(key('det', @name))]/@name">
<xsl:sort/>
<h2>
<xsl:value-of select="."/>
</h2>
<xsl:for-each select="key('det', .)">
<xsl:sort/>
<i>
<xsl:value-of select="title"/>
</i>
<br/>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Any help would me much appreciated!! its probably obvious, but I've
been staring at it for hours....
(The parser we have can work with both xslt 1.0 and 2.0)
Maria.
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