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Re: [xsl] XPath for the selected node

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http://www.topxml.com/code/default.asp?p=3&id=v20010323001030

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Cheers,
Dimitre Novatchev
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Truly great madness cannot be achieved without significant intelligence.
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To invent, you need a good imagination and a pile of junk
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You've achieved success in your field when you don't know whether what
you're doing is work or play

On 7/18/07, v vijith <vvijith@xxxxxxxxx> wrote:

Dear All,
I have an XML which has the structure like

<root>
    <data>
         <node1>Welcome </node1>
         <node2 refid="22">Some data</node2>
     </data>
     <anotherdata>
              <sometype refid=33>welcome</sometype>
      </anotherdata>
</root>

Using Xquery is there a way to find the xpath of all the nodes that
has refid as an attribute? For the above case, the answer that I would
be looking at it

root/data/node2
root/anotherdata/sometype

I went through some of the posts and found that saxon:path is an
option. Do I have any other way of doing it?

Any kind of pointer is appreciated!!

Thanks
Vij

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