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RE: [xsl] comparing a part of the XML tree
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Subject: RE: [xsl] comparing a part of the XML tree From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Mon, 16 Jul 2007 11:47:37 +0100 |
Then you want some $o in original/* satisfies deep-equal(selection/*, $o) or if you prefer original/*[deep-equal(., selection/*)] Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Jethro Borsje [mailto:jethro@xxxxxxxxxxxx] > Sent: 16 July 2007 11:44 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] comparing a part of the XML tree > > >> I can not manage to make the deep-equal function work with > the node() > >> function. > > > > change node() (which is not a function) to * > > > > deep-equal(body/selection/*, body/original/*) > > > This works well when I have 1 element as child of the "original" > element, however when using the following input: > <body> > <selection> > <z color="blue" flavor="vanilla">test 1</z> > </selection> > <original> > <x color="red" flavor="chocolate">test 2</x> > <z color="blue" flavor="vanilla">test 1</z> > </original> > </body> > > With this stylesheet: > <xsl:template match="/"> > <xsl:choose> > <xsl:when test="deep-equal(body/selection/*, > body/original/*)">true</xsl:when> > <xsl:otherwise>false</xsl:otherwise> > </xsl:choose> > </xsl:template> > > It results in "false", while there is a node in <original> > which is equal to the node in <selection>. > > -- > Best regards, > Jethro Borsje > > http://www.jborsje.nl
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