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Re: [xsl] Subsets

Subject: Re: [xsl] Subsets
From: Robert C Corsaro <rcorsaro@xxxxxxxxxxx>
Date: Mon, 23 Apr 2007 16:02:14 -0400

Michael Kay wrote:

I think I got it. node[position() > 1] ... right?

That will give you all nodes of type node in the current context except the first, if that is what you needed, then: yes.
Alternative formulations in XSLT 2.0 are

subsequence(nodes, 2)

remove(nodes, 1)

thanks, that's what I needed :)


Michael Kay
http://www.saxonica.com/

Current Thread
[xsl] Subsets Robert C Corsaro - Mon, 23 Apr 2007 13:38:11 -0400 Robert C Corsaro - Mon, 23 Apr 2007 13:43:39 -0400 Abel Braaksma - Mon, 23 Apr 2007 19:48:40 +0200 Michael Kay - Mon, 23 Apr 2007 19:15:54 +0100 Robert C Corsaro - Mon, 23 Apr 2007 16:02:14 -0400 <= Abel Braaksma - Mon, 23 Apr 2007 19:46:03 +0200 Robert C Corsaro - Mon, 23 Apr 2007 16:01:59 -0400

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RE: [xsl] Subsets, Michael Kay	Thread	Re: [xsl] Subsets, Abel Braaksma
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Re: [xsl] Subsets

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