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Simon Shutter wrote:
//*
//* | //@specific1 | //@specific2
or do you mean:
//* | //specelem/@specific1 | | //specelem/@specific2
But I get the feeling that you want an identity transform of XML, where you want to leave all elements in place, get rid of all attributes except for a few. This can be done like:
HTH,
Re: [xsl] Xpath 1.0 Question : Excluding Attributes?
Subject: Re: [xsl] Xpath 1.0 Question : Excluding Attributes? From: Abel Braaksma <abel.online@xxxxxxxxx> Date: Thu, 29 Mar 2007 01:54:11 +0200 |
Simon Shutter wrote:
Could someone tell me what the Xpath expression is that includes
all element nodes
//*
and only specific attribute children?
//* | //@specific1 | //@specific2
or do you mean:
//* | //specelem/@specific1 | | //specelem/@specific2
But I get the feeling that you want an identity transform of XML, where you want to leave all elements in place, get rid of all attributes except for a few. This can be done like:
<xsl:template match="node()"> <xsl:copy> <xsl:apply-templates select="node() | @*" /> </xsl:copy> </xsl:template>
<!-- throw away all attributes --> <xsl:template match="@*" />
<!-- except these --> <xsl:template match="@specific1 | @specific2"> <xsl:copy /> </xsl:template>
<!-- and these with specific parents --> <xsl:template match="someparent/@specific1"> <xsl:copy /> </xsl:template>
HTH,
Cheers, -- Abel Braaksma http://www.nuntia.nl
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