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Re: [xsl] What's wrong with my ancestor syntax?

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On 3/26/07, Austin, Darrel <Darrel.Austin@xxxxxxxxxxxxxxxxxx> wrote:

I'm trying to use ancestor-or-self.

Here's a sample of the XML:
<menuItems>
 <menuItem>
      <pageID>938</pageID>
      <browserTitle>Home Page</browserTitle>
      <lastUpdate>2006/06/12</lastUpdate>
      <menuItem>
         <pageID>998</pageID>
         <browserTitle>District Administration</browserTitle>
         <lastUpdate>2006/06/06</lastUpdate>
      </menuItem>
 </menuItem>
<menuItems>

This is the XML that forms our site menu. I want to create an RSS feed
that lists the most recent 10 pages that have been changed under a
certain node of the menu.

So, for this example, I want to pass in the page ID of '938' and return
both '938' and any child page underneath it.

Here's the XSL:

<xsl:param name="pageID">1</xsl:param>

<xsl:template match="/">
        <xsl:for-each select="*/menuItem[ancestor-or-self::pageID =
$pageID]">
                <xsl:sort select="substring(@lastUpdate,1,4)"
order="descending" /> <!-- year  -->
                <xsl:sort select="substring(@lastUpdate,6,2)"
order="descending" /> <!-- month -->
                <xsl:sort select="substring(@lastUpdate,9,2)"
order="descending" /> <!-- day   -->
                <xsl:call-template name="createItem" />
        </xsl:for-each>
</xsl:template>

<xsl:template name="createItem">
                lastUpdate: <xsl:value-of select="lastUpdate"/>
                browserTitle: <xsl:value-of select="browserTitle"/>
                pageID: <xsl:value-of select="pageID"/>
</xsl:template>

Originally, I had 'descendant-or-self' by mistake which obviously gave
me the exact opposite of what I wanted and returned the specific node
and all PARENT pages that matched. So I changed to ancestor-or-self and
now it doesn't appear to match anything. I'm not sure why. Is my logic a
bit off?

If I've understood what mean, you just need:

<xsl:template match="/">
 <xsl:apply-templates select="//menuItem[pageID = $pageID">
   <xsl:sort ......./>

and then change the named template to be a match:

<xsl:template match="menuItem">

Also if your dates are yyyy/mm/dd then you can replace your 3 sorts with:

<xsl:sort select="translate(@lastUpdate, '/', '')" data-type="number"/>

cheers
andrew

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