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Oh, for this site, it would be MSXML 4.0
On 2/10/07, Manfred Staudinger <manfred.staudinger@xxxxxxxxx> wrote:
Re: [xsl] Doctype Declerations Imported StyleSheets
Subject: Re: [xsl] Doctype Declerations Imported StyleSheets From: "Karl Stubsjoen" <kstubs@xxxxxxxxx> Date: Sat, 10 Feb 2007 13:37:13 -0700 |
Oh, for this site, it would be MSXML 4.0
On 2/10/07, Manfred Staudinger <manfred.staudinger@xxxxxxxxx> wrote:
Hi Karl,
> XSLT 1.0 Thanks, but still, which processor are you using to process your XSLT 1.0 ?
> So it needs to be part of the child stylesheet? Do you know how this > is specified in the docs so that I can keep my eyes open for this? http://www.w3.org/TR/xslt#output says: The xsl:output element is only allowed as a top-level element.
Manfred
On 10/02/07, Karl Stubsjoen <kstubs@xxxxxxxxx> wrote: > XSLT 1.0 > So it needs to be part of the child stylesheet? Do you know how this > is specified in the docs so that I can keep my eyes open for this? > > On 2/10/07, Manfred Staudinger <manfred.staudinger@xxxxxxxxx> wrote: > > On 10/02/07, Karl Stubsjoen <kstubs@xxxxxxxxx> wrote: > > > If I have a base template and I set the output to: > > > > > > <xsl:output method="html" indent="yes" > > > doctype-public="-//W3C//DTD HTML 4.01//EN" > > > doctype-system="http://www.w3.org/TR/html4/strict.dtd"/> > > > > > > Do I need to call out this doctype again in a template which imports > > > this base template? It seems I do. If I don't, the resulting doctype > > > is different than the doctype called out above. So how does this > > > work? > > What is the processor you are using ? > > XSLT 1.0 or XSLT 2.0 ? > > As the output element has to be a child of the stylesheet element, I think > > you cannot have it in an importet template. > > > > Manfred
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