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RE: [xsl] Using xsl:sort causes transformer to fail

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1. What do you mean when you say it "fails" or "doesn't work"? What are the
symptoms?

2. What does the source XML look like?

3. It looks a very strange sort key, what are you trying to achieve?

Michael Kay
http://www.saxonica.com/


> -----Original Message-----
> From: Sola Awe [mailto:sodana@xxxxxxxxxxx] 
> Sent: 20 January 2007 15:29
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Using xsl:sort causes transformer to fail
> 
> Hi,
>   I have an xsl:sort expression that doesn't always work all 
> the time.  Not sure why.  Here is a segment of my code:
> 
> ------------------------
> xsl:for-each select="$group/ITEM">
>   <xsl:sort 
> select="*[name()=$group/ITEM/*[name()=$rowKey]]/@*[name() = 
> $sortBy]" order="{$sortOrder}" data-type="number"/>
> 
>   <xsl:if test="*[name()=$group/ITEM/*[name()=$rowKey]]">
>     <xsl:call-template name="processItem">
> 	<xsl:with-param name="columnNode"	select="$columnNode"/>
> 	<xsl:with-param name="dataGroup"	select="$group"/>
> 	<xsl:with-param name="rowKey"		
> select="*[name()=$rowKey]"/>
> 	<xsl:with-param name="repeatName" 	
> select="attribute::SORTNAME"/>	        
> </xsl:call-template>
>   </xsl:if>
> </xsl:for-each>
> 
> ----------------------------------
> This is the code that is failing:
>   <xsl:sort 
> select="*[name()=$group/ITEM/*[name()=$rowKey]]/@*[name() = 
> $sortBy]" order="{$sortOrder}" data-type="number"/>
> 
> if, I remove the following from the xsl:sort,
> 
> *[name()=$group/ITEM/*[name()=$rowKey]]/
> 
> The xsl transformation works fine.  However, I need the code 
> above for the sort to work.
> 
> Any suggestions?
> Thanks.

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