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[xsl] Problem with Xpath


Subject: [xsl] Problem with Xpath
From: ms <mina_hurray@xxxxxxxxx>
Date: Wed, 13 Dec 2006 10:39:01 -0800 (PST)

Hi all:

I am having issues with Xpath. 

My xml looks like this:

<root>

<l1>
			<text>
				<para>First level</para>
			</text>
			<info>
				<comp>Kmart</comp>
				<prod>Shoes</prod>
			</info>
			<l2>
			<text>
				<para>Second level .</para>
			</text>
			</l2>
		</l1>
		<l1>
			<text>
				<para>Second level</para>
				<info>
				<comp>Kmart</comp>
				<prod>Shoes</prod>
			</info>
			</text>
		</l1>
			<l1>
			<text>
				<para>Third level</para>
				<info>
				<comp>Target</comp>
				<prod>Pen</prod>
			</info>
			</text>
		</l1>
</root>

Now, I have logic in my style sheet which says that
only if element <l1> contains element <info>, then
if <comp> and <prod> values match the values being
passed to the style sheet through two other parameters
<company> and <product> , then display l1 , otherwise
do not display l1.

The XSLT is :


<xsl:template match="l1">
<xsl:choose>
			<xsl:when test="//info">
				<xsl:if test="//info/company=$company and
//info/product=$product">
					<fo:list-block>
						<fo:list-item>
							<fo:list-item-label>
								<fo:block>
									<xsl:number format="1"/>
								</fo:block>
							</fo:list-item-label>
							<fo:list-item-body>
								<fo:block>
									<xsl:apply-templates/>
								</fo:block>
							</fo:list-item-body>
						</fo:list-item>
					</fo:list-block>
				</xsl:if>
			</xsl:when>
			<xsl:otherwise>
			<!-- Do something else-->
			</xsl:otherwise>
		</xsl:choose>
	</xsl:template>

So, if I have passed $company="KMart" and
$product="Shoes" on the style sheet, then the expected
output is:

1 First
2 Second

Instead, it matches only the company and product for
the first level and stops there. Can you please tell
me what is wrong with the xpath to company and product
on the style sheet?

Thank you in advance for your help. 




 
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