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Subject: [xsl] Problem with Xpath From: ms <mina_hurray@xxxxxxxxx> Date: Wed, 13 Dec 2006 10:39:01 -0800 (PST) |
Hi all: I am having issues with Xpath. My xml looks like this: <root> <l1> <text> <para>First level</para> </text> <info> <comp>Kmart</comp> <prod>Shoes</prod> </info> <l2> <text> <para>Second level .</para> </text> </l2> </l1> <l1> <text> <para>Second level</para> <info> <comp>Kmart</comp> <prod>Shoes</prod> </info> </text> </l1> <l1> <text> <para>Third level</para> <info> <comp>Target</comp> <prod>Pen</prod> </info> </text> </l1> </root> Now, I have logic in my style sheet which says that only if element <l1> contains element <info>, then if <comp> and <prod> values match the values being passed to the style sheet through two other parameters <company> and <product> , then display l1 , otherwise do not display l1. The XSLT is : <xsl:template match="l1"> <xsl:choose> <xsl:when test="//info"> <xsl:if test="//info/company=$company and //info/product=$product"> <fo:list-block> <fo:list-item> <fo:list-item-label> <fo:block> <xsl:number format="1"/> </fo:block> </fo:list-item-label> <fo:list-item-body> <fo:block> <xsl:apply-templates/> </fo:block> </fo:list-item-body> </fo:list-item> </fo:list-block> </xsl:if> </xsl:when> <xsl:otherwise> <!-- Do something else--> </xsl:otherwise> </xsl:choose> </xsl:template> So, if I have passed $company="KMart" and $product="Shoes" on the style sheet, then the expected output is: 1 First 2 Second Instead, it matches only the company and product for the first level and stops there. Can you please tell me what is wrong with the xpath to company and product on the style sheet? Thank you in advance for your help. ____________________________________________________________________________________ Do you Yahoo!? Everyone is raving about the all-new Yahoo! Mail beta. http://new.mail.yahoo.com
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