[XSL-LIST Mailing List Archive Home]
[By Thread]
[By Date]
Try
concat(document('index.xml')/protest/package/name, '.xml')
Spencer
On 12/4/06, chun ji <cji_work@xxxxxxxxx> wrote:
Re: [xsl] new bie question
Subject: Re: [xsl] new bie question From: "Spencer Tickner" <spencertickner@xxxxxxxxx> Date: Mon, 4 Dec 2006 15:45:54 -0800 |
Try
concat(document('index.xml')/protest/package/name, '.xml')
Spencer
On 12/4/06, chun ji <cji_work@xxxxxxxxx> wrote:
I have an index.xml file, which reads as: " -<?xml version="1.0" encoding="ISO-8859-1" ?> -<?xml-stylesheet href="rules.xsl" type="text/xsl"?> -<protest> -<package> -<name>billing</name> -</package> -<package> -<name>timecard</name> -</package> -</protest> ". There is a group of child xml files that associated with each "/protest/package/name", such as "billing.xml", "timecard.xml".
Now I have soming in my XSL file that tries to open all these CHILD xml files, " <xsl:for-each select="document(document('index.xml')/protest/package/name)"> </xsl:for-each> " which fails, because I did not give ".xml" for each child xml.
Does someone know the format to do it ?
thanks a lot
cji
_____________________________________________________________________________ _______
Yahoo! Music Unlimited Access over 1 million songs. http://music.yahoo.com/unlimited
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] new bie question, chun ji | Thread | Re: [xsl] new bie question " openin, chun ji |
[xsl] new bie question, chun ji | Date | Re: [xsl] new bie question " openin, chun ji |
Month |