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hi phil
i'm using
tokenize(document-uri(/), '/')[last()]
or '\' if working with backslashes.
Re: [xsl] Get Document File name
Subject: Re: [xsl] Get Document File name From: Frank Marent <frank.marent@xxxxxxxxxxx> Date: Mon, 23 Oct 2006 08:11:20 +0200 |
hi phil
Is there a way to get the file name of the document you are processing? If I
use Document-uri() it returns the whole file path.
i'm using
tokenize(document-uri(/), '/')[last()]
or '\' if working with backslashes.
regards frank
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